0.3x^2+4x-100=0

Solution for 0.3x^2+4x-100=0 equation:

0.3x^2+4x-100=0

a = 0.3; b = 4; c = -100;
Δ = b2-4ac
Δ = 42-4·0.3·(-100)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{34}}{2*0.3}=\frac{-4-2\sqrt{34}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{34}}{2*0.3}=\frac{-4+2\sqrt{34}}{0.6}
$